Compose functions with valid domains and find inverses only after checking one-to-one behavior.
AA HL
Function fundamentals
Papers 1 and 2
No GDC needed
About 20 min
By the end of this lesson
evaluate and form composite functions
track restrictions through a composition
find and verify an inverse on a suitable domain
Why this matters. An algebraic rule is not a complete function without its domain. Composition and inversion both depend on which inputs are actually allowed.
Composition follows an order
In $(f\circ g)(x)=f(g(x))$, apply $g$ first. The output of $g$ must lie in the domain of $f$.
$x$→$g$→$g(x)$→$f$→$f(g(x))$
Checkpoint
Correct. The input to $f$ is $x-3$, so require $x-3\ge0$.
Not quite. Apply the outer function’s restriction to the inner output, not directly to $x$.
Show explanation
The input to $f$ is $x-3$, so require $x-3\ge0$.
Example 1
Build a composition
Keep the inner function visible
Let $f(x)=\dfrac1{x-2}$ and $g(x)=3x+1$. Find $f(g(x))$ and its domain.
$$f(g(x))=\frac1{(3x+1)-2}=\frac1{3x-1}.$$
The denominator cannot be zero, so $x\ne\frac13$.
Why not just use $x\ne2$?
The input reaching $f$ is $g(x)$, so require $g(x)\ne2$. This gives $3x+1\ne2$.
Check one-to-one before inverting
An inverse reverses a function. It is a function only when each output of the original rule comes from one allowed input.
Checkpoint
Correct. Both $a$ and $-a$ give the same output. Restricting to $x\ge0$ or $x\le0$ makes the rule one-to-one.
Not quite. $\pm\sqrt{x}$ is not a single-valued function, and the unrestricted square function fails the horizontal-line test.
Show explanation
Both $a$ and $-a$ give the same output. Restricting to $x\ge0$ or $x\le0$ makes the rule one-to-one.
Example 2
Find an inverse
Reverse each operation
Find the inverse of $f(x)=\dfrac{2x-5}{3}$.
Write $y=f(x)$
$$y=\frac{2x-5}{3}$$
Solve for $x$
$$3y=2x-5\Rightarrow x=\frac{3y+5}{2}$$
Rename the input
$$f^{-1}(x)=\frac{3x+5}{2}.$$
A check gives $f(f^{-1}(x))=x$.
Order the method
Put these inverse steps in a sensible order.
Write $y=f(x)$ and interchange the roles of input and output
Solve the resulting equation for $y$
State the inverse domain and range
Check a composition gives $x$
Show a valid order
Write $y=f(x)$ and interchange the roles of input and output
Solve the resulting equation for $y$
State the inverse domain and range
Check a composition gives $x$
The algebra, restrictions and verification now follow logically.
Example 3
Restrict, then invert
A quadratic branch
Let $h(x)=(x-1)^2+4$ for $x\ge1$. Find $h^{-1}$.
$$y=(x-1)^2+4\Rightarrow x-1=\sqrt{y-4}$$
The positive root is required because $x\ge1$.
$$h^{-1}(x)=1+\sqrt{x-4},\qquad x\ge4.$$
The inverse graph is the reflection of the restricted branch in $y=x$.
In the exam
Quick check
Five questions to check the main decisions from this lesson.
Your score is not saved.
$g$ produces the input used by $f$.
Show explanation
$g$ produces the input used by $f$.
Reverse adding $1$, then multiplying by $2$.
Show explanation
Reverse adding $1$, then multiplying by $2$.
Two different inputs can give the same output.
Show explanation
Two different inputs can give the same output.
Inversion exchanges coordinates $(x,y)$ and $(y,x)$.
Show explanation
Inversion exchanges coordinates $(x,y)$ and $(y,x)$.
Both occurrences of $1/x$ require a non-zero input.
Show explanation
Both occurrences of $1/x$ require a non-zero input.
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